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C++ = How to sum of digits of any number code.

Code no: 1 = By using array. 

#include <iostream>

using namespace std;

int main() 

{

int number;

cout<<"Enter the n";

cin>>number;

int a[number];

int sum=0;

cout<<"Enter a digit : "<<endl;

for (int i=1;i<=number;i++)

{

cin>>a[i];

}

for (int i=1;i<=number;i++)

{

sum+=a[i];

}

cout<<"The sum of the number : "<<sum;

return 0;

}
Result:








Code no: 2 = By using some logic without using array and all the code is in one function.

#include <iostream>

using namespace std;

int main()

{

int num,origional,sum=0,digit=0;

origional=num;

cout<<"Enter any no: to finds its sum = ";

cin>>num;

while(num!=0)

{

digit=num%10;

sum+=digit; 

num/=10; 

}

cout<<"The sum of the digits is "<<sum;

return 0;

}

Result:






Code no: 3 = Using same code as of code no: second but using different function to perform same task.

#include <iostream>

using namespace std;

int sumofdigit(int num)

{

int sum=0,digit=0;

while (num!=0)

{

digit=num%10;

sum+=digit;

num/=10;

}

return sum;

}

int main()

{

int num;

cout<<"Enter any digit to find its sum = ";

cin>>num;

    int sum=sumofdigit(num);

cout<<"Sum of the digit is "<<sum;

return 0;

}

Result:




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